Question

What is the mass of 1.24 x 10^23 molecules of N2O2

Answer 1

12.4 g N₂O₂

General Formulas and Concepts:

Chemistry

Atomic Structure

• Reading a Periodic Table
• Moles
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 1.24 × 10²³ molecules N₂O₂

[Solve] grams N₂O₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of N₂O₂ - 2(14.01) + 2(16.00) = 60.02 g/mol

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 1.24 \cdot 10^(23) \ molecules \ N_2O_2((1 \ mol \ N_2O_2)/(6.022 \cdot 10^(23) \ molecules \ N_2O_2))((60.02 \ g \ N_2O_2)/(1 \ mol \ N_2O_2))`
2. [DA] Divide/Multiply [Cancel out units]:
   `\displaystyle 12.3588 \ g \ N_2O_2`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

12.3588 g N₂O₂ ≈ 12.4 g N₂O₂