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Answer:


\text{log}_a(1.5^(-1))=(-9)/(5)

Explanation:

Given;


\text{log}_a(2)=(1)/(2)


\text{log}_a(3)=5

By using logarithmic properties,


\text{log}_a(2)-\text{log}_a(3)=(1)/(2)-5


\text{log}_a((2)/(3))=(1)/(2)-5


\text{log}_a((1)/((3)/(2)))=(1)/(2)-5


\text{log}_a((1)/(1.5))=(1)/(2)-5


\text{log}_a(1.5^(-1))=(1-10)/(5)


\text{log}_a(1.5^(-1))=(-9)/(5)

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