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What is the center of the circle: (x+3)^2+y^2=16 ?
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What is the center of the circle: (x+3)^2+y^2=16 ?

User Frank Kalis
by
6.3k points

1 Answer

2 votes

Answer:

the answer is (-3,0) or 4

Explanation:

User Varun Maggo
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