Question

12.0 g NaHSO4 (MM: 120.1 g/mol) is dissolved in water to make a 2.00 L solution. What is the molarity of the resulting NaHSO4 solution?

Answer 1

The molarity of the resulting NaHSO₄ solution is 0.05
`(moles)/(liter)`

Step-by-step explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

`Molarity=(moles of solute)/(volume)`

Molarity is expressed in units
`(moles)/(liter)`.

Molar mass is the amount of mass that a substance contains in one mole. Being the molar mass of the compound NaHSO₄ equal to 120.1 g/mole, then the number of moles that 12 grams contain is calculated by:

`12 g*(1 mole)/(120.1 g) = 0.1 moles`

And being 2 L the volume of the solution, then replacing in the definition of molarity you get:

`Molarity=(0.1 moles)/(2 L)`

Molarity= 0.05
`(moles)/(liter)`

The molarity of the resulting NaHSO₄ solution is 0.05
`(moles)/(liter)`

Answer 2

0.05 M

Step-by-step explanation:

First we convert 12 g of NaHSO₄ into moles, using the given molar mass:

• 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄

We can now calculate the molarity of the resulting solution, using the calculated number of moles and the given volume:

• Molarity = moles / liters

• Molarity = 0.10 mol / 2.00 L = 0.05 M