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Trigonometry please help! work need to be shown

Trigonometry please help! work need to be shown-example-1

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Given:

The figure of a right angle triangle.

To find:

The value of x to the nearest hundredth.

Solution:

In a right angle triangle,


\cos \theta=(Base)/(Hypotenuse)

Using the above trigonometric ratio for the given triangle, we get


\cos 46^\circ=(x)/(8)


0.6947=(x)/(8)


0.6947* 8=x


5.5576=x

Approximate the value to the nearest hundredth.


x\approx 5.56

Therefore, the value of x is 5.56 units.

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