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1 vote
8. Determine the area of a sector

with a central angle of 42° in a
circle with radius 3 inches.

NEED IT ASAP

User Ilya Bibik
by
8.2k points

1 Answer

3 votes

Answer:


\boxed {\boxed {\sf A \approx 3.3 \ in^2}}

Explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.


A= \frac {\theta}{360}* \pi r^2

The angle is 42 degrees and the radius is 3 inches. Therefore,


\theta= 42 \\r=3 \ in


A=\frac {42}{360} * \pi (3 \ in)^2

Solve the exponent.

  • (3 in)²= 3 in*3in = 9 in²


A=\frac {42}{360} * \pi (9 \ in^2)

Multiply all three numbers together.


A= 0.116666666667* 3.14159265359 * 9 \ in^2


A=3.29867228627 \ in^2

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.


A \approx 3.3 \ in^2

The area of the sector is approximately 3.3 square inches.

User Gergely Kovacs
by
9.0k points

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