Answer:
-1 and 4/3
Explanation:
Given the quadratic equation;
f(x) = 3x^2-x-4
To get all potential roots, we will equate f(x) = 0
3x^2-x-4 = 0
3x^2-4x+3x-4 = 0
x(3x-4)+1(3x-4) = 0
(x+1)(3x-4) = 0
x+1= 0 and 3x-4 = 0
x = -1 and 3x = 4
x = -1 and x= 4/3
Hence the potential roots are -1 and 4/3