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Which equation has infinitely many solutions? A. 6x + 5 = 6x + 7 B. 6x + 7 = 5x + 7 C. 3(x + 2) – 1 = 3x + 1 D. 4(x + 1) – 3 = 4x + 1
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4 votes
Which equation has infinitely many solutions?

A. 6x + 5 = 6x + 7
B. 6x + 7 = 5x + 7
C. 3(x + 2) – 1 = 3x + 1
D. 4(x + 1) – 3 = 4x + 1

User Karolszafranski
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1 Answer

5 votes
For C and D do distributive
3x + 6 - 1 = 3x + 1
4x + 4 - 3 = 4x + 1
Only D is true

The solution is D
User Riba
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3.8k points
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