Question

Help pls i don't know how to solve this

Answer 1

x = - 8 and (- 8, 0 )

Explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the equation of the axis of symmetry which is also the x- coordinate of the vertex is

x = -
`(b)/(2a)`

y = x² + 16x + 64 ← is in standard form, with

a = 1 and b = 16, then

x = -
`(16)/(2)` = - 8

Equation of axis of symmetry is x = - 8

Substitute x = - 8 into the quadratic and evaluate for y

y = (- 8)² + 16(- 8) + 64 = 64 - 128 + 64 = 0

vertex = (- 8, 0 )