Question

How much NaCl would you dissolve and dilute to the 100.00 mL mark in a volumetric flask with DI H2O to prepare a 0.825 M sodium chloride solution?

Answer 1

4.82 g

Step-by-step explanation:

To solve this problem we'll use the definition of molarity:

• Molarity = moles / liters

We are given the volume and concentration (keep in mind that 100mL=0.100L):

• 0.825 M = moles / 0.100 L

Now we calculate the number of NaCl moles required:

• moles = 0.0825 mol

Then we convert 0.0825 NaCl moles into grams, using its molar mass:

• 0.0825 mol * 58.44 g/mol = 4.82 g