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The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0 …

The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0 …
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The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve.

x + y = 0
x^2 - y^2 = -2
x^2 + y^2 = 16
x^2 + y^2 = 8

User MinhD
by
8.4k points

2 Answers

2 votes

Answer:

.

Explanation:

.

User Thegeko
by
8.7k points
5 votes

Answer:

i belive its x^2 + y^2 = 8

Explanation:

User Alexandros
by
8.4k points
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