SOLUTION OF Q4
A) x + 2y = 3 , 5x - 4y = 8
=) x = 3 - 2y
Substituting x = 3 - 2y in 5x - 4y = 8, we get;
=) 5 (3-2y) - 4y = 8
=) 15 - 10y - 4y = 8
=) -14y = 8 - 15
=) y = - 7/ -14
=) y = 1/2
Now, by putting y = 1/2 in x + 2y = 3, we get;
=) x + 2(1/2) = 3
=) x + 1 = 3
=) x = 3 - 1
=) x = 2
The value of x is 2 and y is 1/2.
C) 2m + n = 2 , 3m - 2n = 3
=) n = 2 - 2m
Substituting n = 2 - 2m in 3m - 2n = 3, we get;
=) 3m - 2 (2-2m) = 3
=) 3m - 4 + 4m = 3
=) 7m = 3+ 4
=) m = 7/7
=) m = 1
Now, by putting m = 1 in 2m + n = 2, we get;
=) 2(1) + n = 2
=) 2 + n = 2
=) n = 2-2
=) n = 0
the value of m is 1 and n is 0.