Question

Find the 10th term of 3, 9 /2​ , 27/4

Answer 1

Explanation:

the nth term of a geometric sequence is

∙

x

a

n

=

a

r

n

−

1

where a is the first term and r the common ratio

r

=

a

2

a

1

=

a

3

a

2

=

...

...

=

a

n

a

n

−

1

here

a

=

3

and

r

=

9

3

=

27

9

=

3

⇒

a

10

=

3

×

3

9

=

3

10

=

59049