Question

The potential difference between the two plates of a capacitor is 8. 5 v. If the separation between the plates is 4. 1 mm, what is the strength of the electric field between the plates n/c?.

Answer 1

Hello!

We can use the following equation:

`V = Ed`

V = Potential Difference (V)

E = Electric Field (N/C)

d = distance between plates (m)

Begin by converting 4.1 mm to m.

1 mm = 0.001 m

4.1 mm = 0.0041 m

Now, we can solve for the electric field strength.

`E = (V)/(d) = (8.5)/(0.0041) = \boxed{2037.17 (N)/(C)}`