Question

If 0.0015 moles of NaOH is dissolved in 11 L of water, what is the pH of the
solution?

Answer 1

pH = 10.15

Step-by-step explanation:

NaOH is a strong base so it dissolves completely.

Calculate your [OH-] first by dividing the moles of OH- by the volume.

0.0015 mol OH- / 11 L = 0.00014

Then, calculate the pOH:

pOH = -log[OH-] = -log(0.00014) = 3.85

pOH + pH = 14, so pH = 14 - pOH = 14 - 3.85 = 10.15