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Solve 64y=9y^3 I need a good step-by-step please

User Maneesh
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2 Answers

6 votes
64 = 9y^3

Divide through by 9y

64/9=y^2

y^2=64/9

y= √(64/9) or -√(64/9)

y=8/3 or -8/3
y=2 2/3 or -2 2/3
User Me Sa
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3.1k points
11 votes

Answer:


y = \frac83, y = -\frac83

Explanation:

Solve:


  • 64y = 9y^3

  • 64 = 9y^2 \text{ divide both sides by y}

  • (64)/(9) = y^2 \text{ divide both sides by 9}

  • \sqrt{(64)/(9)} = √(y^2)

  • \frac83 = |y|

  • y = \frac83, y = -\frac83

Use rule: √a² = |a|

-Chetan k

User Zadam
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