Question

Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other

Answer 1

Answer:
`1.298* 10^(-5)\ N/m`

Step-by-step explanation:

Given

Current in the first wire
`I_1=2.2\ A`

Current in the second wire
`I_2=5.9\ A`

wires are
`20\ cm` apart

Force per unit length between the current-carrying wires is

`\Rightarrow (F)/(l)=(\mu_oI_1I_2)/(2\pi r)`

Force exerted by the wires is the same

Put the values

`\Rightarrow (F)/(l)=f=(4\pi * 10^(-7)* 2.2* 5.9)/(2\pi * 0.2)=1.298* 10^(-5)\ N/m`

This force will be repulsive in nature as the current is flowing opposite