Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ
Step-by-step explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
Putting the values we get :
2 moles of butane releases heat = 5314.8 kJ
1 mole of butane release heat =

Thus enthalpy of combustion per mole of butane is -2657.4 kJ