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PLEASE I NEED HELP!

What is the mass of a sample of glass ( specific heat - 0.50J/kg*"C), if it requires 490 J of heat to raise the temperature from 18.0°C to 0.0°C?​

User Dqd
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Answer:

Q=mc∆tita.

490J= m× 0.5J/Kg/C × (18-0°C)

490J= m × 9J/kg

490J

9J/Kg = m.

m= 54.4Kg