Question

Worth a lot of points!

Express the following equation in the form ax^2+bx+c=0:
(4a+3)^2=(a+5)(a−2)

Answer 1

15a² + 21a + 19 = 0

Explanation:

Given

(4a + 3)² = (a + 5)(a - 2)

(4a + 3)(4a + 3) = (a + 5)(a - 2 ) ← expand both sides using FOIL

16a² + 24a + 9 = a² + 3a - 10 ( subtract a² + 3a - 10 from both sides )

16a² - a² + 24a - 3a + 9 + 10 = 0 ← collect like terms

15a² + 21a + 19 = 0