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What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 45% solution?
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What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 45% solution?

User WLGfx
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1 Answer

3 votes

Answer:

400 mL

Explanation:

0.50x + 0.20(600-x) = 0.40*600

50x + 20*600 - 20x = 40*600

30x = 20*600

x = 20*20

x = 400 mL

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