Question

A spinner has 9 equal sections numbers 1-9. Determine the probability of spinning an odd number twice.

Answer 1

25 /81

Explanation:

Sample space = (1, 2, 3, 4, 5, 6, 7, 8, 9)

Probability = required outcome / Total possible outcomes

Odd numbers in sample space = (1, 3, 5, 7, 9) = 5

Required outcome = odd numbers = 5

Total possible outcomes = sample space = 9

P(odd outcome) = 5 /9

P(odd number twice) = 5/9 * 5/9 = 25 /81