Question

Debbie is ordering a breakfast special at a diner that comes with eggs, bread, and a drink. The special offers the following options:

• The eggs can be scrambled or fried.
• The bread options are a biscuit, a slice of toast, or a bagel.
• The drinks options are orange juice, apple juice, coffee, or tea.
• Debbie will randomly choose each option in the breakfast special.
What is the probability Debbie
will choose fried eggs, toast,
and either coffee or tea?

A. 1/12
B. 4/9
C. 4/5
D. 1/24

Answer 1

The probability Debbie will choose fried eggs, toast, and either coffee or tea is;

A. 1/12

Explanation:

From the question, we have;

The number of options for preparing the eggs = 2 options

Therefore, the probability of either egg option chosen = 1/2

The number of options for the type of bread = 3

Therefore, the probability of either bread option chosen = 1/3

The number of options for the drink = 4

Therefore, the probability of either drink option chosen = 1/4

We add probabilities connected with an 'or' statement and multiply probabilities connected with an 'and' as follows;

The probability for Debbie to choose either coffee or tea = 1/4 + 1/4 = 1/2

Therefore, the probability Debbie will choose fried eggs, (and) toast, and either coffee (or) tea, P is given as follows;

P = 1/2 × 1/3 × 1/2 = 1/12

The probability Debbie will choose fried eggs, toast, and either coffee or tea = 1/12.