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I need help please please

I need help please please-example-1
User Zhichao
by
2.7k points

1 Answer

14 votes
14 votes

Answer: (4.4, 3)

This point is marked as point Q in the diagram below.

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Step-by-step explanation:

Check out the diagram below.

I've added point P to the figure which is located at (11, 1)

This forms triangle DPS.

The horizontal side of the triangle is 11 units long as it spans from x = 0 to x = 11.

We need to split the horizontal side into the ratio 2:3. In other words, we need to split it into 2 equal parts and 3 equal parts as shown in the diagram. There are 2+3 = 5 parts total.

Each part is 11/5 = 2.2 units wide.

Two such parts will have a width of 2*2.2 = 4.4

Notice how 4.4 is the x coordinate of point Q.

This is the result of adding 4.4 to the x coordinate of D.

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The vertical distance from P to S is 5 units. Split this into five equal parts and each part is 5/5 = 1 unit tall.

Two parts will be 2*1 = 2 units tall.

We'll add 2 on the y coordinate of D to get 2+1 = 3.

The y coordinate of point Q is 3.

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Point Q is located at (4.4, 3) which splits the segment DS into the ratio 2:3

In other words, the ratio of segments DQ to QS is 2:3

We could write that like DQ:QS = 2:3

Or we could say DQ/QS = 2/3.

I need help please please-example-1
User Vinayak Pingale
by
2.8k points
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