What is [H+] in a solution with a pH = 1.82?

Kelly Cook asked Aug 12, 2023

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Kelly Cook asked Aug 12, 2023

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8 votes

$\\ \tt\Rrightarrow pH=-log[H^+]$

$\\ \tt\Rrightarrow 1.82=-log[H^+]$

$\\ \tt\Rrightarrow log[H^+]=-1.82$

$\\ \tt\Rrightarrow [H^+]=10^(-1.82)$

$\\ \tt\Rrightarrow [H^+]=0.015M$

Squawknull answered Aug 16, 2023

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