Answer:
The material is 6 out of 7 times likely to support a load above 1,000 pounds
Explanation:
From the data in the given question, we have;
1,200, 1,400, 1,300, 1,500, 950, 1,600, 1,100
Therefore, we have;
The number of trials that the material has been used, n = 7 trials
The number of trials the material holds more than 1,000 pounds, P(W>1,000) = 6 trials
The probability that the material can hold more than 1,000 pounds, 'P' is given as follows;
P = P(W>1,000)/n
∴ P = 6/7
Therefore, the material is 6 out of 7 times likely to support a load above 1,000 pounds