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A compound has a percent composition of 15.24% sodium (molar mass = 22.99 g/mol), 52.95% bromine (molar mass = 79.90 g/mol), and 31.81% oxygen (molar mass = 16.00 g/mol). Assuming that the mass of the
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A compound has a percent composition of 15.24% sodium (molar mass = 22.99 g/mol), 52.95% bromine (molar mass = 79.90 g/mol), and 31.81% oxygen (molar mass = 16.00 g/mol). Assuming that the mass of the compound is 100 g, what is the compound’s empirical formula?

User Sajalsuraj
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5 votes

Answer:

NaBrO3

Step-by-step explanation:

See table above.

A compound has a percent composition of 15.24% sodium (molar mass = 22.99 g/mol), 52.95% bromine-example-1
User Josh Bode
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