Question

A package is dropped from a flying plane. The package, which had a zero initial vertical velocity, falls with an open

parachute at a constant acceleration of 3.6 m/s?
How long, in seconds, will it take for the package to fall a vertical distance of 45 m?

Answer 1

5s

Step-by-step explanation:

s = ut + (1/2)at^2

45 = 1/2 x 3.6 x t^2

t = 5s