Question

A uniform meter rule is balanced by 80N and 20N from its ends. Find the position of its pivot from the 20N end. Show your working please

Answer 1

80 cm

Step-by-step explanation:

From the diagram attached,

Sum of clockwise moment = sum of anticlockwise

ΣACW = ΣCW

20x = 80(100-x)

Solve for x

20x = 8000-80x

20x+8x = 8000

100x = 8000

x = 8000/100

x = 80 cm.

The position of its pivot from the 20 N end is 80 cm.