Answer:
![Area = 287\ in^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/runm459n8f2r4qsxyrlm2xluvli11g8xih.png)
Explanation:
Given
![Length = 20.5](https://img.qammunity.org/2022/formulas/mathematics/high-school/khkwtr5qgfsxivsieoqx2ld9jvps4otgox.png)
![Space = 4.25](https://img.qammunity.org/2022/formulas/mathematics/high-school/s4au9wr10niu9sxg8byp0pyk3yrh3fd3h4.png)
![Panels = 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/443g7hvgyowi3ca6614k74czhjm3iw66yi.png)
See attachment
Required
The area of one panel
From the attachment, the total width is 50.5in.
i.e.
![Total\ Width = 50.5](https://img.qammunity.org/2022/formulas/mathematics/high-school/nlta88pgfn3ildk2w2itz760t6bezcinmz.png)
Given that there are 2 spaces between the 3 panels and each space has a length of 4.25 in.
The reduced width is:
![Reduced\ Width = 50.5 - 2 * 4.25](https://img.qammunity.org/2022/formulas/mathematics/high-school/ob658egam9hp03au7ns6b84heh1moxzzoy.png)
![Reduced\ Width = 42](https://img.qammunity.org/2022/formulas/mathematics/high-school/ssmzlirl5pg1ce9xqv79t3r21niceglym3.png)
At this point, we can calculate the width of one panel by dividing the reduced width by the number of panels (3).
![Width = (42)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/nukkxpetiinjoe4mjbgurxh18oyu4m95qv.png)
![Width = 14](https://img.qammunity.org/2022/formulas/mathematics/high-school/1q1oy8xwduebg3wpgw9ws41ca7qnkkw5oe.png)
The area of one is:
![Area = Length * Width](https://img.qammunity.org/2022/formulas/mathematics/college/14jjiqkh69peazba6khve5dmx2929knauy.png)
![Area = 20.5 * 14](https://img.qammunity.org/2022/formulas/mathematics/high-school/jyge5ojqo1m70nj1u743eu8wj8uif4pgqv.png)
![Area = 287\ in^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/runm459n8f2r4qsxyrlm2xluvli11g8xih.png)