Question

10) 81 grams of Au is how many mL ?

Answer 1

Answer: Thus 81 grams of Au is 9210 ml

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

`\text{moles of Au}=(81g)/(196.96g/mol)=0.411moles`

1 mole of Au occupies = 22.4 L

Thus 0.411 moles of Au occupy =
`(22.4)/(1)* 0.411=9.21L=9210ml`

81 grams of Au is 9210 ml