Answer:
Explanation:
Part A
x-intercepts of the graph → x = 0, 6
Maximum value of the graph → f(x) = 120
Part B
Increasing in the interval → 0 ≤ x ≤ 3
Decreasing in the interval → 3 < x ≤ 6
As the price of goods increase in the interval [0, 3], profit increases.
But in the price interval of (3, 6] profit of the company decreases.
Part C
Average rate of change of a function 'f' in the interval of x = a and x = b is given by,
Average rate of change =
![(f(b)-f(a))/(b-a)](https://img.qammunity.org/2022/formulas/mathematics/high-school/txs1euguzec6r5gr7avzpjl0wwupu6x4ca.png)
Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,
Average rate of change =
![(f(3)-f(1))/(3-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/r8owj7mr0gymjljpavh03fyagug11xqg57.png)
=
![(120-60)/(3-1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ttsp1poqygcmgck1lofy4k4gs1v0fgjgnc.png)
= 30