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Calculus Help Please!!

If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then k=
I know the answer is the square root of 12 but I don’t know how to get there.

Calculus Help Please!! If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then-example-1

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Answer: K=sqrt 12

Step-by-step explanation:

When it's |k^2+4|=4 you had to complete the square to get |(k+2)(k-2)+8|=4

Calculus Help Please!! If integral^k_0 x/(x^2 + 4) dx = 1/2 ln(4), where k > 0, then-example-1
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