Question

What is an equation of a circle whose center is (1,4) and diameter is 10?

Question options:

x2 − 2x + y2 − 8y = 83


x2 − 2x + y2 − 8y = 8


x2 + 2x + y2 + 8y = 8


x2 + 2x + y2 + 8y = 83

Answer 1

`x^(2) - 2x + y^(2) - 8y = 8`

Explanation:

Standard form for a circle is:

`(x - h)^(2) + (y - k)^(2) = r^(2)` (h, k) is the center r is the radius

`(x - 1)^(2) + (y - 4)^(2) = 5^(2) \\x^(2) - 2x + 1 +y^(2) - 8y + 16 = 25\\x^(2) - 2x + y^(2) - 8y = 8`
`x^(2) - 2x + y^(2) - 8y = 8`