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A volume of 20.0L of oxygen is warmed from -30.0C to SATP condition. What is the new volume if the pressure is kept constant

User Pranita
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1 Answer

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V1/T1 = V2/T2

V1 = 20.0 L
T1 = -30.0°C = 243 K
T2 = 273 K

20.0/243 = V2/273

V2 = 22.5 L
User Bogdan Ustyak
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