Question

Calculate the mass, in grams, of 0.540 mol of manganese (Mn).

Report your answer with three significant figures.

Answer 1

m = 29.6 grams

Step-by-step explanation:

Given that,

Number of moles = 0.540

The molar mass of manganese = 54.93 g/mol

We know that,

Number of moles = given mass/molar mass

`m=n* M\\\\m=0.540 * 54.93\\\\m=29.6\ g`

So, the required mass of the Manganese is equal to 29.6 grams.