Question

The sum of five consecutive multiples of 4 is 20.Find the smallest integer.

Answer 1

The smallest integer is -4.

Explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

`(5x)/(5) = (-20)/(5)`

x = -4

∴ the smallest integer is -4.

Hope this helps!!!