Answer:
A
Explanation:
Calculate the lengths of JK and JL using the distance formula
d =
![\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }](https://img.qammunity.org/2022/formulas/mathematics/high-school/bvn9gyn3kb5znjatyo0ybqks09f51n4oea.png)
with (x₁, y₁ ) = J(2, 1) and (x₂, y₂ ) = K(- 4, 2)
JK =
![√((-4-2)^2+(2-1)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/hrms5l3frnohz4ukb49zgb5bf4fh21cfzn.png)
=
![√((-6)^2+1^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/12wgk5hsh4ueb71y4sf2prq0klt0xljwxq.png)
=
![√(36+1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/am1u8fk3tquokiyg0do3e99wdysd6zf2sx.png)
=
≈ 6.1 units
Repeat with (x₁, y₁ ) = J(2, 1) and (x₂, y₂ ) = L(7, 4)
JL =
![√((7-2)^2+(4-1)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/qy5yt4u5racnx8d41qabui0fwrm52egojk.png)
=
![√(5^2+3^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/waes86p1yh515re8cgjzt8cq9csdkvb5mo.png)
=
![√(25+9)](https://img.qammunity.org/2022/formulas/mathematics/college/elzjcapbu61nx2wixcuzisk8agmuimv4mw.png)
=
≈ 5.8 units
Thus JK is longer than JL → A