Question

How many moles of ethanol are produced starting with 500.g glucose?

C6H12O6 → 2 C2H5OH + 2 CO2

Answer 1

5.55 mol C₂H₅OH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Tables
• Moles

Stoichiometry

• Using Dimensional Analysis
• Analyzing Reactions RxN

Step-by-step explanation:

Step 1: Define

[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

[Given] 500. g C₆H₁₂O₆ (Glucose)

[Solve] moles C₂H₅OH (Ethanol)

Step 2: Identify Conversions

[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH

[PT] Molar mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

Step 3: Stoichiometry

1. [DA] Set up conversion:
   `\displaystyle 500 \ g \ C_6H_(12)O_6((1 \ mol \ C_6H_(12)O_6)/(180.18 \ g \ C_6H_(12)O_6))((2 \ mol \ C_2H_5OH)/(1 \ mol \ C_6H_(12)O_6))`
2. [DA} Multiply/Divide [Cancel out units]:
   `\displaystyle 5.55001 \ mol \ C_2H_5OH`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH