Answer:
Q = mcΔt
Step-by-step explanation:
Specific heat capacity of water = 4.18 J °C g
Mass of water = 50g
Δt = 100 - 20 = 80°C
Q = (50) x (4.18) x (80)
Q = 16720 J is required to raise the temperature of the water
Q = 50 g x 4.184 J/g°c (100 - 20)°C
Q = 16736 J
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