Question

A triangle has sides that are in a ratio of 3:5:6. If the perimeter of the triangle is 42, what

is the measure of the smallest side of the triangle?

Answer 1

Answer:
9cm or m (You havent mentioned any
Explanation:
the total of the ratio of 3sides is (3+5+6) 14
That 14 = 42cm / m
So we have to find 1 part by dividing 42 by 14
1 part = 3 cm/m
The smallest ratio among 3:5:6 is 3 .
so if 1 part is equal to 3cm/m,
3×3
9cm/m