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In the diagram, mZBDA = 150°. Find mZBDC.

In the diagram, mZBDA = 150°. Find mZBDC.-example-1
User Vijesh VP
by
3.4k points

2 Answers

18 votes
18 votes

Answer:

Your answer is ∠BDC = 70°

Explanation:

So you know that the total angle is 150°. Given that, we can set the two equations equal to 150° because we know that they add to 150°.

-3x + 34 + -2x + 56 = 150

First, combine the like terms.

-3x - 2x = -5x

34 + 56 = 90

-5x + 90 = 150

Get the -5x by itself by subtracting 90 from 150.

150 - 90 = 60

Now you have:

-5x = 60

Get the x alone by dividing both sides by -5.

-5x/-5 = 1x (written as just x, though)

60/-5 = -12

Therefore, x = -12.

__________________________________________________________

Given that x = -12, We can substitute -12 in place of "x" into the equation desired to solve, in this case that angle we want to solve for is ∠BDC.

∠BDC is represented by the equation (-3x + 34)

Substitute -12 in place of x and solve.

-3(-12) +34

36 + 34

= 70

Therefore ∠BDC = 70°.

User TractorPulledPork
by
3.3k points
23 votes
23 votes

Answer:


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Explanation:


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(Angle sum postulate)


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User Bob Paulin
by
2.7k points