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PLEASE HELP FAST(solve the pre-algebra question)

PLEASE HELP FAST(solve the pre-algebra question)-example-1
User Steros
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1 Answer

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Answer:

Flag = 46

Shamrock = 46

Hat = 27

Accordion = 198

Explanation:

To keep things simple, I'll denote the flag with f, the shamrock with s, the hat with h and the accordion with a.

The second equation tells us that f/s is 1. When you divide something by something and get 1, that means they're equal (eg, 2÷2=1, 3÷3=1 etc). That means f=s.

The second equation tells us f+s+s=138, but since f=s, this basically means 3f=138. Dividing both sides by three, we find out f=46 and by extension, s=46.

The third equation tells us s+h+h=100. We know s so we can write this as 46+2h=100. Take 46 form both sides to get 2h=54. Divide both sides by 2, we find out h=27.

The fourth equation tells us a=4f+14. Sub in our value for f and this is a=(4x46)+14. Solve this to get a=184+14, a=198.

User Quester
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