Register
A small town had a population of 9,800 in 2005. Now, it is 6,300. Write an expression to find the percent of change. What is the percent of change? Round to the nearest tenth.
132k views
5 votes
A small town had a population of 9,800 in 2005. Now, it is 6,300. Write an expression to find the percent of change. What is the percent of change? Round to the nearest tenth.

User Matthias Braun
by
7.5k points

1 Answer

2 votes

Answer:

  • 35.7% decrease

Explanation:

Change in population:

  • 9800 - 6300 = 3500 (decrease)

Percent change:

  • 3500/9800*100% = 35.7% (rounded to the nearest tenth)
User Waleed Khan
by
8.5k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!