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the volume of a soap bubble is 2,308.4 mm ^3. Find the radius and diameter of the soap bubble. Use 3.14 for pi​

User Vbezhenar
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1 Answer

6 votes

Answer:

r = 8.2mm

d = 816.4mm

Explanation:

Let the soap be spherical in nature

Volume of a sphere = 4/3 πr³

r is the radius

Given that V = 2308.4mm^3

Substitute

2308.4 = 4/3 πr³

2308 = 4/3 (3.14)r³

2308.4 * 3 = 12.56r³

6,925.2 = 12.56r³

r³ = 6,925.2 /12.56

r³ = 551.37

r = 8.2mm

diameter = 2r

diameter = 2(8.2)

diameter = 16.4mm

User Rankthefirst
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