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What are the solutions of the equation
-12x+26=-(1/5)-x+2+3

User Shakib
by
3.5k points

1 Answer

1 vote

Answer:

Explanation:

Expand -(1/5)-x+2+3

-(1/5)-x+2+3

Remove the parenthesis;

=1/5-x+2+3

Add the numbers; 2+3=5

=-x+5-1/5

Convert element to fraction;

=5*5-1/5

Since the denominators are equal combine the fractions;

5*5/5-1/5

5*5-1=24

Multiply the numbers;5*5=25

=25-1

Subtract the numbers:25-1=24

=24

=-x+24/5

-12x+26=-x+24/5

Subtract 26 from both sides;

-12x+26-26=-x+24/5-26

Simplify;

-12x+26-26

Add similar elements; 26-26=0

=-12x

Simplify;-x+24/5-26

Convert element to fraction;

- 26/*5/5+24/5

Since the denominators are equal , combine the fractions;

-26*5+24

Multiply the numbers; 25*5=130

=-130+24

Add/subtract the number;-130+24=-106

=-106

=-106/5

Apply the fraction rule;

=-x-106/5

-12x=-x-106/5

Add x to both sides;

-12x+x=-x-106/5+x

Simplify;

-11x+=-106/5

Divide both sides by -11

-11x/-11=-106/5/-11

Simplify ;-11x/-11

Divide ;11/11

=1

=x

simplify;-106/5/-11

Apply fraction rule; 106/5/11

106/5*11

Multiply the numbers;5*11=55

=106/55

x=106/55

User Izza
by
3.9k points