Answer:
Part A: There are 6 possible outcomes of this experiment.
Part B: There are 6 possible outcomes of the experiment ; red, brown, green, white, black, and blue ( equal)
Part C:
Sample Space = { red, brown, green, white, black, blue }
Part D:
P (blue)= 1/6
Part E:
P (not purple)= 1
Explanation:
Part A:
There are 6 possible outcomes of this experiment.
As there are 6 pairs of socks. Each pair is folded together so that the socks cannot be mixed up . There is 1 chance of choosing each pair of socks.
Part B:
The chosen socks can be any of the following red, brown, green, white, black, and blue so there are 6 possible outcomes of the experiment ; red, brown, green, white, black, and blue (all have equal probability) .
Part C:
The sample space contains all the possible outcomes of the event.
Sample Space = { red, brown, green, white, black, blue }
Part D:
P(blue)= No of favorable outcomes/ Total no of outcomes
P (blue)= 1/6
Part E:
P (not purple)= 1
As the total probability is always equal to 1 and we want to find the probability of the color which is not given in the list
P( purple) = 0/6= 0
And the probability of not purple is given by the formula
P (not purple) = 1- P (purple)
= 1-0= 1
1 indicates that the event of any other color except purple must occur which is equal to the probability of not purple.
This can be solved by complement rule also.