Question

Electrochemical cells can be used to measure ionic concentrations. A cell is set up with a pair of Zn electrodes, each immersed in ZnSO4 solution. One solution is created to be exactly 0.300 M, and the potential on its electrode is measured to be 0.045 V higher than the other electrode. What is the concentration of the other solution

Answer 1

the concentration of the solution is 0.00906 M

Step-by-step explanation:

Given the data in the question;

we know that from Nernst Equation;

E = E⁰ - ((0.0592/n) logQ)

now, E₀ for concentration cell is 0

n for this redox is 2

concentration of the unknown solution is x

so we substitute

0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))

0.045 = -0.0296log( x/0.300 )

divide both side by 0.0296

1.52 = -log( x/0.300 )

x/0.300 =

x/0.300 = 0.0301995

we cross multiply

x = 0.300 × 0.0301995

x = 0.00906 M

Therefore, the concentration of the solution is 0.00906 M