115k views
4 votes
im supposed to solve this, but im first supposed to convert the bases to be the same and thats what im struggling with​

im supposed to solve this, but im first supposed to convert the bases to be the same-example-1
User Swagg
by
6.9k points

1 Answer

6 votes

9514 1404 393

Answer:

1

Explanation:

From your knowledge of multiplication tables, you know that ...

8 = 2×2×2 = 2³

4 = 2×2 = 2²

so the problem can be rewritten as ...


(8^4)/(4^6)=((2^3)^4)/((2^2)^6)=(2^(3\cdot4))/(2^(2\cdot6))=(2^(12))/(2^(12))=\boxed{1}

__

The applicable rule of exponents is ...

(a^b)^c = a^(bc)

______

Alternate solution

You could use 8^2 = 64 and 4^3 = 64. Then this is (8^2)^2/(4^3)^2 = 64^2/64^2, where the common base is 64, not 2.

User Vadym Chekan
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.