Question

Can someone please help me with math.

Answer 1

1. 10 pigs and 12 geese

2. 20 and 80

2. pretzel would be 3 dollars

Explanation:

i had the same question and got it right

Answer 2

Explanation:

3) Number of pigs = p

Number of geese = g

p + g = 20 --------------(I)

p = 20 - g --------------(II)

4p + 2g = 64 ----------------------(III)

Substitute p = 20 - g in (III)

4*(20 - g) + 2g = 64

4*20 - 4*g + 2g = 64

80 - 4g + 2g = 64 {Combine like terms}

80 - 2g = 64 {Subtract 80 form both sides}

-2g = 64 - 80

-2g = - 16 {Divide both sides by (-2)}

g = -16/-2

g = 8

Plugin g = 8 in equation (II)

p = 20 - 8

P = 12

Number of pigs = 12

4) Let the number be x , y

x + y = 100 ---------------(I)

x = 4y --------------(II)

Substitute x = 4y in equation (I)

4y + y = 100

5y = 100

y = 100/5

y = 20

Plugin y = 20 in equation (II)

x = 4*20 = 80

x = 80

Smaller number = 20

5) Cost of soda = s

Cost of pretzel = p

2s + p = 7 --------------(I)

p = 7 - 2s -------------(II)

4s + 3p = 17 --------------(III)

Substitute p = 7 - 2s in (III)

4s + 3*(7 - 2s) = 17

4s + 3*7 - 3*2s = 17

4s + 21 - 6s = 17

21 - 2s = 17

-2s = 17 -21

-2s = -4

s = -4/-2

s = 2

Plugin s = 2 in (II)

p = 7 - 2*2

= 7 - 4

p = 3

Cost of soda = $ 2

Cost of pretzel = $ 3